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Question
$y=3x+1$
$4x+y=10$
Step1: Substitute $y=3x+1$ into the second equation
Substitute $y = 3x + 1$ into $4x + y = 10$:
$4x + (3x + 1) = 10$
Step2: Simplify and solve for $x$
Combine like terms and isolate $x$:
$7x + 1 = 10$
$7x = 10 - 1$
$7x = 9$
$x = \frac{9}{7}$
Step3: Substitute $x$ to find $y$
Plug $x = \frac{9}{7}$ into $y = 3x + 1$:
$y = 3\times\frac{9}{7} + 1 = \frac{27}{7} + \frac{7}{7} = \frac{34}{7}$
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$x=\frac{9}{7}$, $y=\frac{34}{7}$