Question

the measure of angle a is 15°, and the length of side bc is 8. what are the lengths of the other two sides, rounded to the nearest tenth? ab = <u> </u> ac = <u> </u>

Explanation:

Step1: Use tangent for AC

$\tan(A)=\frac{BC}{AC}$, so $AC = \frac{BC}{\tan(A)}=\frac{8}{\tan(15^{\circ})}\approx 29.9$.

Step2: Use sine for AB

$\sin(A)=\frac{BC}{AB}$, so $AB=\frac{BC}{\sin(A)}=\frac{8}{\sin(15^{\circ})}\approx 30.9$.

Answer:

AB = 30.9
AC = 29.9