Question

the measures of the angles of a triangle are shown in the figure below. solve for x.$(3x+4)^{circ}LXB0(3x-19)^{circ}$answer$x = $

Explanation:

Step1: Sum angles to 180°

$$(3x+4) + (3x-19) + 45 = 180$$

Step2: Simplify left side

$$6x + 30 = 180$$

Step3: Isolate $6x$ term

$$6x = 180 - 30$$
$$6x = 150$$

Step4: Solve for $x$

$$x = \frac{150}{6}$$

Answer:

$x=25$