QUESTION IMAGE
Question
z is the midpoint of \\(\overline{xy}\\) and \\(\overline{wz} \perp \overline{xy}\\). complete the proof that \\(\overline{wy} \cong \overline{wx}\\).
image of a triangle with vertices w, x, y and midpoint z on xy, with wz perpendicular to xy
| statement | reason |
|---|---|
| 2. \\(\overline{wz} \perp \overline{xy}\\) | given |
| 3. \\(\angle wzx \cong \angle wzy\\) | all right angles are congruent |
| 4. \\(\overline{xz} \cong \overline{yz}\\) | |
| 5. \\(\overline{wz} \cong \overline{wz}\\) | |
| 6. \\(\triangle wxz \cong \triangle wyz\\) | |
| 7. \\(\overline{wy} \cong \overline{wx}\\) | cpctc |
Step1: Reason for midpoint segments
Definition of midpoint: A midpoint divides a segment into two congruent parts. So $\overline{XZ} \cong \overline{YZ}$ because Z is the midpoint of $\overline{XY}$.
Step2: Reason for reflexive congruence
Reflexive Property of Congruence: A segment is congruent to itself. So $\overline{WZ} \cong \overline{WZ}$ by this property.
Step3: Reason for triangle congruence
Side-Angle-Side (SAS) Congruence Postulate: We have two pairs of congruent sides ($\overline{XZ} \cong \overline{YZ}$, $\overline{WZ} \cong \overline{WZ}$) and a pair of congruent included right angles ($\angle WZX \cong \angle WZY$). Thus $\triangle WXZ \cong \triangle WYZ$ by SAS.
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- Reason: Definition of midpoint
- Reason: Reflexive Property of Congruence
- Reason: Side-Angle-Side (SAS) Congruence Postulate