Question

1. model: to determine the probability of a trait combination such as black fur and red eyes, consider each trait separately. fill in the punnett square for each trait. then determine the probability of black fur and the probability of red eyes. express each probability as a fraction. parent 1 fur genotype: fl parent 2 fur genotype: fl parent 2 fur genotype: ee

Explanation:

Step1: Set up Punnett - square for fur trait

For two parents with fur genotype $Ff$ and $Ff$, the possible gametes are $F$ and $f$ from each parent. The Punnett - square has 4 cells: $(F,F)$, $(F,f)$, $(f,F)$, $(f,f)$.

	F	f
f	Ff	ff

The probability of having a dominant - fur genotype (FF or Ff) is $\frac{3}{4}$ and the probability of having a recessive - fur genotype (ff) is $\frac{1}{4}$. But we don't know which is black and which is non - black from the given information. Assuming $F$ is for black fur, the probability of black fur is $\frac{3}{4}$.

Step2: Since no information about eye - color genotypes

We cannot calculate the probability of red eyes. But if we assume we only need to find the probability of black fur based on the fur genotypes given, the probability of black fur (assuming $F$ is the allele for black fur) is $\frac{3}{4}$.

Answer:

The probability of black fur is $\frac{3}{4}$ (assuming $F$ is the allele for black fur and no information about eye - color probability calculation as no eye - color genotypes are given).