Question

the monthly mean salaries and standard deviations of four college students are given by the table (student, mean, standard deviation: clarissa, $345, 12.53; abi, $598, 8.99; kaila, $812, 15.29; shenika, $208, 7.67). which statement must be true? options: the monthly salary of shenika is less spread out than the monthly salary of clarissa. the monthly salary of kaila is less spread out than the monthly salary of abi. the monthly salary of abi is less spread out than the monthly salary of shenika. the monthly salary of clarissa is less spread out than the monthly salary of abi.

Explanation:

Standard deviation measures the spread of data values. A smaller standard deviation means less spread. We compare the standard deviations of each pair:

1. Shenika (7.67) vs Clarissa (12.53): 7.67 < 12.53, so Shenika's salary is less spread out.
2. Kaila (15.29) vs Abi (8.99): 15.29 > 8.99, so Kaila's salary is more spread out.
3. Abi (8.99) vs Shenika (7.67): 8.99 > 7.67, so Abi's salary is more spread out.
4. Clarissa (12.53) vs Abi (8.99): 12.53 > 8.99, so Clarissa's salary is more spread out.

Answer:

The monthly salary of Shenika is less spread out than the monthly salary of Clarissa.