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question id: 110138
deena has 2 pairs of white socks, 3 pairs of black socks, 1 pair of red socks, and 2 pairs of navy socks in her sock drawer. each pair of socks is folded together. if she pulls a pair of socks out of her drawer in the morning without looking, what is the probability that she will choose a pair of white socks?
options:
$\frac{2}{5}$
$\frac{1}{4}$
$\frac{3}{5}$
$\frac{2}{3}$
Step1: Calculate total pairs of socks
Total pairs = 2 (white) + 3 (black) + 1 (red) + 2 (navy) = 8.
Step2: Calculate probability of white socks
Probability = $\frac{\text{Number of white pairs}}{\text{Total pairs}}$ = $\frac{2}{8}$ = $\frac{1}{4}$? Wait, no, wait: 2+3+1+2=8? Wait 2+3 is 5, 5+1 is 6, 6+2 is 8? Wait no, 2 (white) + 3 (black) is 5, +1 (red) is 6, +2 (navy) is 8? Wait no, 2+3=5, 5+1=6, 6+2=8? Wait, no, 2+3 is 5, plus 1 is 6, plus 2 is 8? Wait, but 2 (white) + 3 (black) +1 (red) +2 (navy) = 2+3=5, 5+1=6, 6+2=8. So total pairs are 8? Wait, but the option has 1/4? Wait, no, wait 2 (white) divided by 8 total? 2/8 is 1/4. Wait, but let me check again. Wait 2 white, 3 black, 1 red, 2 navy. So 2+3+1+2=8. So number of white pairs is 2. So probability is 2/8 = 1/4. Wait, but the first option is 2/5, which is 0.4, 1/4 is 0.25, 3/5 is 0.6, 2/3 is ~0.666. Wait, maybe I miscalculated total pairs. Wait 2 (white) + 3 (black) is 5, +1 (red) is 6, +2 (navy) is 8? Wait, no, 2+3=5, 5+1=6, 6+2=8. Yes. So 2 white out of 8 total. 2/8 simplifies to 1/4. So the answer should be 1/4.
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$\frac{1}{4}$ (corresponding to the option $\frac{1}{4}$)