QUESTION IMAGE
Question
the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer. match each compound inequality on the left to the graph that represents its solution on the right. -14 ≤ 6x + 4 < 16 -4x + 3 > -9 and -6x ≤ 12 -4x + 3 < -9 or 6x ≤ -12 click and hold an item in one column, then drag it to the matching item in the other column. be sure your cursor is over the target before releasing. the target will highlight or the cursor will change. need help? watch this video. clear
Step1: Solve the first compound - inequality
Solve \(-14\leq6x + 4<16\). First, subtract 4 from all parts: \(-14-4\leq6x+4 - 4<16 - 4\), which simplifies to \(-18\leq6x<12\). Then divide all parts by 6: \(\frac{-18}{6}\leq\frac{6x}{6}<\frac{12}{6}\), so \(- 3\leq x<2\).
Step2: Solve the second compound - inequality
For \(-4x + 3>-9\) and \(-6x\leq12\).
- Solve \(-4x + 3>-9\): Subtract 3 from both sides: \(-4x+3 - 3>-9 - 3\), so \(-4x>-12\). Divide both sides by - 4 and reverse the inequality sign: \(x < 3\).
- Solve \(-6x\leq12\): Divide both sides by - 6 and reverse the inequality sign: \(x\geq - 2\). The solution is \(-2\leq x<3\).
Step3: Solve the third compound - inequality
For \(-4x + 3<-9\) or \(6x\leq - 12\).
- Solve \(-4x + 3<-9\): Subtract 3 from both sides: \(-4x+3 - 3<-9 - 3\), so \(-4x<-12\). Divide both sides by - 4 and reverse the inequality sign: \(x>3\).
- Solve \(6x\leq - 12\): Divide both sides by 6: \(x\leq - 2\). The solution is \(x\leq - 2\) or \(x>3\).
Match the solutions to the graphs based on the endpoints and open/closed - circle rules (closed circle for \(\leq\) or \(\geq\), open circle for \(<\) or \(>\)).
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
Match \(-14\leq6x + 4<16\) to the graph with a closed - circle at \(-3\) and an open - circle at 2.
Match \(-4x + 3>-9\) and \(-6x\leq12\) to the graph with a closed - circle at \(-2\) and an open - circle at 3.
Match \(-4x + 3<-9\) or \(6x\leq - 12\) to the graph with a closed - circle at \(-2\) and an open - circle on the right - hand side for \(x>3\) and including values \(x\leq - 2\).