Question

ms. carlson goes for a jog every morning. the line plot shows the number of miles she jogged each day for the last two weeks. how many miles did she jog in total? a 15 b 28 c 53 d 55

Explanation:

Step1: Count x's per mile

• 1 mile: 1 x → \(1\times1 = 1\)
• 2 miles: 2 x's → \(2\times2 = 4\)
• 3 miles: 2 x's → \(3\times2 = 6\)
• 4 miles: 4 x's → \(4\times4 = 16\)
• 5 miles: 3 x's → \(5\times3 = 15\)
• 6 miles: 1 x → \(6\times1 = 6\)
• 7 miles: 1 x → \(7\times1 = 7\)

Step2: Sum all products

\(1 + 4 + 6 + 16 + 15 + 6 + 7 = 55\)? Wait, no, recalculate:
1 (1) + 4 (2×2) + 6 (3×2) + 16 (4×4) + 15 (5×3) + 6 (6×1) + 7 (7×1)
1 + 4 = 5; 5 + 6 = 11; 11 + 16 = 27; 27 + 15 = 42; 42 + 6 = 48; 48 + 7 = 55? Wait, but let's check again. Wait, maybe I miscounted x's:

• 1 mile: 1 x (correct)
• 2 miles: 2 x's (correct)
• 3 miles: 2 x's (correct)
• 4 miles: 4 x's (correct)
• 5 miles: 3 x's (correct)
• 6 miles: 1 x (correct)
• 7 miles: 1 x (correct)

Wait, but 1×1=1, 2×2=4, 3×2=6, 4×4=16, 5×3=15, 6×1=6, 7×1=7. Sum: 1+4=5; +6=11; +16=27; +15=42; +6=48; +7=55. But option D is 55? Wait, but let's check the line plot again. Wait, maybe I made a mistake. Wait, 1 mile: 1 x, 2 miles: 2 x's, 3 miles: 2 x's, 4 miles: 4 x's, 5 miles: 3 x's, 6 miles: 1 x, 7 miles: 1 x. So total miles:
1(1) + 2(2) + 3(2) + 4(4) + 5(3) + 6(1) + 7(1)
= 1 + 4 + 6 + 16 + 15 + 6 + 7
= (1+4) + (6+16) + (15+6) + (7)
= 5 + 22 + 21 + 7
= 5 + 22=27; 27+21=48; 48+7=55. Wait, but the options have D as 55. Wait, but maybe I miscounted x's. Wait, let's count x's per column:

• 1: 1
• 2: 2
• 3: 2
• 4: 4
• 5: 3
• 6: 1
• 7: 1

Yes, so sum is 1×1 + 2×2 + 3×2 + 4×4 + 5×3 + 6×1 + 7×1 = 1 + 4 + 6 + 16 + 15 + 6 + 7 = 55. Wait, but the options: D is 55. Wait, but let me check again. Wait, maybe I added wrong. 1+4=5, +6=11, +16=27, +15=42, +6=48, +7=55. Yes. So the total is 55.

Answer:

D. 55