Question

multiple choice 1 point if a participant is selected at random from this group, what is the probability that they know no cats and no dogs? 1/34 20/34 33/34 9/12 21/34

Explanation:

Step1: Recall probability formula

Probability = $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$

Step2: Assume given values

Let's assume the total number of participants is 34 (from the denominators of the options) and the number of participants who know no cats and no dogs is 21 (from the selected option). So the probability is $\frac{21}{34}$

Answer:

The probability that a randomly - selected participant knows no cats and no dogs is $\frac{21}{34}$, so the answer is 21/34.