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8 multiple choice 0.5 points between a and b, the velocity is closest t…

Question

8 multiple choice 0.5 points between a and b, the velocity is closest to: ar. to and e? which x (meters) 6 5 e 4 a 3 2 d 1 b c t (hours) 1 2 3 4 5 6 -1 m/s -1.67 m/s 1.67 m/s 0 m/s

Explanation:

Step1: Identify coordinates of A and B

Point A: $(t_A, x_A) = (0, 4)$; Point B: $(t_B, x_B) = (1.5, 1.5)$

Step2: Calculate displacement

$\Delta x = x_B - x_A = 1.5 - 4 = -2.5$ meters

Step3: Calculate time interval

$\Delta t = t_B - t_A = 1.5 - 0 = 1.5$ hours

Step4: Convert time to seconds

$\Delta t = 1.5 \times 3600 = 5400$ seconds

Step5: Compute average velocity

$v = \frac{\Delta x}{\Delta t} = \frac{-2.5}{5400} \approx -0.00046$ m/s? Correction: Recognize unit error in options, use hours directly then convert to m/s equivalent
Wait, correct: The options use m/s but graph uses hours, likely a unit typo, treat time in hours as hours for velocity in m/h then convert to m/s:
$v = \frac{-2.5}{1.5} \approx -1.67$ m/h, convert to m/s: $\frac{-1.67}{3600}$ is wrong. Correct: The options must have a unit error, intended time is hours as x-axis, velocity is $\frac{\Delta x}{\Delta t} = \frac{1.5-4}{1.5-0} = \frac{-2.5}{1.5} \approx -1.67$ m/h, but options say m/s, this is a typo, the intended answer is -1.67, matching the option assuming time is in hours (the graph's x-axis is hours, so the options likely mislabeled units, should be m/h, but the value is -1.67)

Answer:

-1.67 m/s