Question

multiple choice (single sol... 1 point how many of the following ordered pairs are solutions of the equation ( 3x + 2y = 12 )? ① ( (x,y) = (2,3) ); ② ( (x,y) = (4,0) ); ③ ( (x,y) = (0,6) ); ④ ( (x,y) = (1,5) ) a 1 b 2 c 3 d 4

Explanation:

Step1: Test pair (2,3)

Substitute $x=2, y=3$ into $3x+2y$:
$3(2)+2(3)=6+6=12$

Step2: Test pair (4,0)

Substitute $x=4, y=0$ into $3x+2y$:
$3(4)+2(0)=12+0=12$

Step3: Test pair (0,6)

Substitute $x=0, y=6$ into $3x+2y$:
$3(0)+2(6)=0+12=12$

Step4: Test pair (1,5)

Substitute $x=1, y=5$ into $3x+2y$:
$3(1)+2(5)=3+10=13
eq12$

Step5: Count valid pairs

3 ordered pairs satisfy the equation.

Answer:

C 3