Question

multiply.
$3ab\left(xa^{9}+ya^{3}+9\
ight)$
$3ab\left(xa^{9}+ya^{3}+9\
ight)=\square$

Explanation:

Step1: Distribute 3ab to each term

$3ab \cdot xa^9 + 3ab \cdot ya^3 + 3ab \cdot 9$

Step2: Multiply coefficients and combine exponents

$3x a^{1+9}b + 3y a^{1+3}b + 27ab$

Step3: Simplify exponents

$3x a^{10}b + 3y a^{4}b + 27ab$

Answer:

$3a^{10}bx + 3a^{4}by + 27ab$