Question

multiplying and dividing rational expressions
rewrite the expression completely.
view solution history
perform multiplication
\\(\boldsymbol{\frac{w + 3}{15w - 3} cdot \frac{5w - 1}{w^2 - 1}}\\)
enter the result.

Explanation:

Step1: Factor all expressions

$15w-3=3(5w-1)$, $w^2-1=(w+1)(w-1)$

Step2: Rewrite the original expression

$\frac{w+3}{3(5w-1)} \cdot \frac{5w-1}{(w+1)(w-1)}$

Step3: Cancel common factors

Cancel $(5w-1)$ from numerator and denominator:
$\frac{w+3}{3} \cdot \frac{1}{(w+1)(w-1)}$

Step4: Multiply remaining terms

$\frac{w+3}{3(w+1)(w-1)}$ or expand denominator: $\frac{w+3}{3(w^2-1)} = \frac{w+3}{3w^2-3}$

Answer:

$\boldsymbol{\frac{w+3}{3(w+1)(w-1)}}$ (or equivalent expanded form $\boldsymbol{\frac{w+3}{3w^2-3}}$)