QUESTION IMAGE
Question
y = mx + b. graph the following. determine the point where the lines intersect!
first set of equations and graph:
$y = -x - 1$
$y = x - 3$
graph
second set:
$y = \frac{1}{2}x - 1$
$y = -\frac{3}{4}x + 4$
graph
third set:
$y = -x + 1$
$y = 4$
graph
fourth set:
$y = -\frac{1}{2}x + 4$
$x = 4$
graph
fifth set:
$y = -4x - 2$
$y = -x + 1$
graph
sixth set:
$y = \frac{1}{2}x + 3$
$y = -\frac{5}{2}x - 3$
graph
- is the point (-3, 5) a solution to $y = \frac{2}{3}x + 7$?
show work!
- graph a line with
$x$-intercept = (-5,0)
$y$-intercept = (0, 3)
graph
- given $f(x) = \frac{3}{4}x - 6$
find $f(8) = $
find $x$ so that $f(x) = 18$
- given $h(x) = \frac{2}{3}x - 4$ fill in the table.
| $x$ | $h(x)$ |
|---|---|
| -3 | |
| 24 |
- solve for $y$ then state the slope of the line. $4x - 3y = 15$
$m = $
Top Section: Intersection Points of Lines
For each pair of lines, set equations equal and solve.
Step1: Set equations equal
$y=-x-1$; $y=x-3$
$-x-1=x-3$
Step2: Solve for $x$
$-2x=-2 \implies x=1$
Step3: Find $y$
$y=1-3=-2$
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Step1: Set equations equal
$y=\frac{1}{2}x-1$; $y=-\frac{3}{4}x+4$
$\frac{1}{2}x-1=-\frac{3}{4}x+4$
Step2: Solve for $x$
$\frac{2}{4}x+\frac{3}{4}x=5 \implies \frac{5}{4}x=5 \implies x=4$
Step3: Find $y$
$y=\frac{1}{2}(4)-1=1$
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Step1: Set equations equal
$y=-x+1$; $y=4$
$-x+1=4$
Step2: Solve for $x$
$-x=3 \implies x=-3$
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Step1: Set equations equal
$y=-\frac{1}{2}x+4$; $x=4$
Step2: Find $y$
$y=-\frac{1}{2}(4)+4=2$
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Step1: Set equations equal
$y=-4x-2$; $y=-x+1$
$-4x-2=-x+1$
Step2: Solve for $x$
$-3x=3 \implies x=-1$
Step3: Find $y$
$y=-(-1)+1=2$
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Step1: Set equations equal
$y=\frac{1}{2}x+3$; $y=-\frac{5}{2}x-3$
$\frac{1}{2}x+3=-\frac{5}{2}x-3$
Step2: Solve for $x$
$3x=-6 \implies x=-2$
Step3: Find $y$
$y=\frac{1}{2}(-2)+3=2$
Step1: Substitute $x=-3$ into equation
$y=\frac{2}{3}(-3)+7$
Step2: Calculate right-hand side
$y=-2+7=5$
Plot the x-intercept $(-5,0)$ and y-intercept $(0,3)$ on the grid, then draw a straight line connecting the two points.
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