Question

name: tianna sid ohms law practice problems calculate the current in following circuits, show your work: 1. i = \frac{v}{r}=5\frac{8}{5}=18\omega 5\frac{3}{5}=\frac{i}{18}=0.5a 2. i = \frac{v}{r}=2.5\frac{3}{5.5}\omega v = 1.5v 2.5\frac{3}{5.5}=\frac{15}{45}=\frac{1}{30}=0.27a 3.

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is $I=\frac{V}{R}$, where $I$ is current, $V$ is voltage, and $R$ is resistance.

Step2: Solve for the first circuit

The total resistance $R = 5 + 8+5=18\Omega$, and $V = 9V$. Using Ohm's Law, $I=\frac{V}{R}=\frac{9}{18}=0.5A$.

Step3: Solve for the second circuit

The total resistance $R=2.5 + 3=5.5\Omega$, and $V = 1.5V$. Then $I=\frac{V}{R}=\frac{1.5}{5.5}=\frac{15}{55}=\frac{3}{11}\approx0.27A$.

Step4: Solve for the third circuit

The total resistance $R=2.5+20 = 22.5\Omega$, and $V = 1.5V$. So $I=\frac{V}{R}=\frac{1.5}{22.5}=\frac{15}{225}=\frac{1}{15}\approx0.067A$.

Answer:

1. $0.5A$
2. $\frac{3}{11}A\approx0.27A$
3. $\frac{1}{15}A\approx0.067A$