Question

navigation begin date: 9/11/2025 12:01:00 am due date: 9/12/2025 11:59:00 pm end date: 9/14/2025 11:59:00 pm problem 10: (3% of assignment value) a person lives at latitude 27° in the northern hemisphere. part (a) how high above the horizon (in degrees) is the north celestial pole where this person lives? h = 27.00 ° correct! part (b) how far is it (in degrees) from the north celestial pole to the zenith where this person lives? θ =

Explanation:

Step1: Recall the relationship

The angle between the north - celestial pole and the zenith is related to the latitude. The sum of the angle of the north - celestial pole above the horizon (which is equal to the latitude in the Northern Hemisphere) and the angle between the north - celestial pole and the zenith is 90 degrees.
Let the latitude be $\lambda = 27^{\circ}$ and the angle between the north - celestial pole and the zenith be $\theta$. Then $\lambda+\theta = 90^{\circ}$.

Step2: Solve for $\theta$

We can rewrite the equation as $\theta=90^{\circ}-\lambda$.
Substitute $\lambda = 27^{\circ}$ into the equation: $\theta = 90 - 27$.
$\theta=63^{\circ}$

Answer:

$63$