QUESTION IMAGE
Question
negative exponent and zero exponent properties
- $a^{-7} = $
- $(21c^{18})^{-1} = $
- $(3d^2)^0 = $
- $5(x^0)y^{-1} = $
Step1: Apply negative exponent rule
$a^{-n}=\frac{1}{a^n}$, so $a^{-7}=\frac{1}{a^7}$
Step2: Apply negative exponent to product
$(21c^{18})^{-1}=\frac{1}{21c^{18}}$
Step3: Apply zero exponent rule
Any non-zero term to 0 power is 1, so $(3d^2)^0=1$
Step4: Simplify zero and negative exponents
First, $x^0=1$, then $y^{-1}=\frac{1}{y}$. So $5(x^0)y^{-1}=5\times1\times\frac{1}{y}=\frac{5}{y}$
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
- $\frac{1}{a^7}$
- $\frac{1}{21c^{18}}$
- $1$
- $\frac{5}{y}$