(- negative) velocity (m/s) vs. time (s): entire jump
8 the slope of a velocity vs time (v vs t) graph is the...
(a)
a acceleration
b position
c time
d velocity
(b) calculate the acceleration from 0s to 50s. you must show your work to receive credit.
(c) show your work below. use the guess method
givens
unknown
(- negative) velocity (m/s) vs. time (s): end of jump

Question

Accepted Answer

### Part (a)
# Brief Explanations:
In physics (a subfield of Natural Science), the slope of a velocity - time (v - t) graph is defined as the rate of change of velocity with respect to time. The formula for slope in a v - t graph is $m=\frac{\Delta v}{\Delta t}$, and acceleration $a$ is also defined as $a = \frac{\Delta v}{\Delta t}$. Position is related to the area under the v - t graph, time is the independent variable on the x - axis, and velocity is the dependent variable on the y - axis. So the slope of a v - t graph is acceleration.
# Answer:
A. Acceleration

### Part (b) (assuming we can estimate values from the graph: Let's assume at $t = 0$, $v=0$ m/s and at $t = 50$ s, from the first graph (Entire Jump), let's assume the velocity $v = 380$ m/s (approximate from the y - axis scale))
# Explanation:
## Step1: Recall the formula for acceleration
Acceleration $a$ is given by the formula $a=\frac{\Delta v}{\Delta t}$, where $\Delta v=v_f - v_i$ and $\Delta t=t_f - t_i$.
## Step2: Identify initial and final values
We assume $v_i = 0$ m/s (at $t_i = 0$ s) and $v_f=380$ m/s (at $t_f = 50$ s). So $\Delta v=380 - 0=380$ m/s and $\Delta t = 50 - 0 = 50$ s.
## Step3: Calculate acceleration
Substitute the values into the formula: $a=\frac{380}{50}=7.6$ m/s².
# Answer:
The acceleration from 0 to 50 s is approximately $\boldsymbol{7.6}$ m/s² (the value may vary depending on the exact reading from the graph)

### Part (c) (using the GUESS method)
# Explanation:
## Step1: G (Givens)
- Initial velocity, $v_i = 0$ m/s (at $t = 0$ s)
- Final velocity, $v_f$ (let's say from the graph at $t = 50$ s, $v_f = 380$ m/s)
- Initial time, $t_i = 0$ s
- Final time, $t_f = 50$ s

## Step2: U (Unknown)
We need to find the acceleration, $a$.

## Step3: E (Equation)
The equation for acceleration is $a=\frac{\Delta v}{\Delta t}=\frac{v_f - v_i}{t_f - t_i}$

## Step4: S (Substitute)
Substitute the given values into the equation: $a=\frac{380 - 0}{50 - 0}=\frac{380}{50}$

## Step5: S (Solve)
$\frac{380}{50}=7.6$ m/s²
# Answer:
- Givens: $v_i = 0$ m/s, $v_f = 380$ m/s, $t_i = 0$ s, $t_f = 50$ s
- Unknown: Acceleration ($a$)
- Equation: $a=\frac{v_f - v_i}{t_f - t_i}$
- Substitute: $a=\frac{380 - 0}{50 - 0}$
- Solve: $a = 7.6$ m/s²

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QUESTION IMAGE

Question

Explanation:

Part (a)

Step1: Recall the formula for acceleration

Step2: Identify initial and final values

Step3: Calculate acceleration

Step1: G (Givens)

Step2: U (Unknown)

Step3: E (Equation)

Step4: S (Substitute)

Step5: S (Solve)

Answer:

Part (b) (assuming we can estimate values from the graph: Let's assume at $t = 0$, $v=0$ m/s and at $t = 50$ s, from the first graph (Entire Jump), let's assume the velocity $v = 380$ m/s (approximate from the y - axis scale))