Question

next, cancel common factors.
lim_{x \to 4} \frac{x(x - 4)}{(x - 4)(x + 1)}=lim_{x \to 4}\frac{x}{square}

Explanation:

Step1: Cancel common factor

Cancel out the common factor $(x - 4)$ in the numerator and denominator of the fraction $\frac{x(x - 4)}{(x - 4)(x + 1)}$.
$\lim_{x
ightarrow4}\frac{x(x - 4)}{(x - 4)(x + 1)}=\lim_{x
ightarrow4}\frac{x}{x + 1}$

Step2: Substitute $x = 4$

Substitute $x = 4$ into the function $\frac{x}{x+1}$.
$\lim_{x
ightarrow4}\frac{x}{x + 1}=\frac{4}{4 + 1}=\frac{4}{5}$

Answer:

$\frac{4}{5}$