Question

normally distributed sample means: mastery test
1
type the correct answer in the box. use numerals instead of words. if necessary, use / for the fraction bar.
the mean of a population being sampled is 64, and the standard deviation is 6.
if the sample size is 50, the standard error of the mean is. (round off your answer to the nearest hundredth.)

Explanation:

Step1: Recall the formula

The formula for the standard error of the mean is $\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}$, where $\sigma$ is the population standard - deviation and $n$ is the sample size.

Step2: Substitute the given values

We are given that $\sigma = 6$ and $n = 50$. So, $\sigma_{\bar{x}}=\frac{6}{\sqrt{50}}$.

Step3: Calculate the value

$\sqrt{50}\approx7.071$, then $\frac{6}{7.071}\approx0.85$.

Answer:

0.85