Question

now, multiply -2 by the second term, 4, to finish writing the left side of the equation without parentheses. \\(10 - 2(h + 4)\\)\\(=\\)\\(3h - 8\\)\\(10 + -2(h + 4)\\)\\(=\\)\\(3h - 8\\)\\(10 + -2h + \square\\)\\(=\\)\\(3h - 8\\)

Explanation:

Step1: Apply distributive property

We need to expand $-2(h+4)$. By the distributive property $a(b+c)=ab+ac$, we get:
$-2(h+4) = -2h + (-2)\times4$

Step2: Calculate the constant term

Compute $(-2)\times4$:
$(-2)\times4 = -8$
So $-2(h+4) = -2h -8$, which means $10 + (-2)(h+4) = 10 -2h -8$.

Step3: Match to find the missing term

Compare $10 + -2h + \square$ to $10 -2h -8$. The missing term is $-8$.

Answer:

$-8$