Question

now solve for the second partial product, and look at each place value one at a time.
solve 9 tens·6.
$4.36\cdot9.3\approx36$
$\

$$\begin{array}{r}436\\\\×\\quad93\\\\\\hline1,308\\\\□\\\\□□\\end{array}$$

$

Explanation:

Step1: Rewrite 9 tens as value

9 tens = $9 \times 10 = 90$

Step2: Multiply by 6

$90 \times 6 = 540$

Step3: Align with partial product

For $436 \times 93$, the second partial product is $436 \times 90 = 39240$, which fills the boxes as 3 9 2 4 (with the trailing 0 shown).

Answer:

The second partial product is 39240, so the boxes are filled with $\boldsymbol{3}$, $\boldsymbol{9}$, $\boldsymbol{2}$, $\boldsymbol{4}$ (and the trailing 0), and $9$ tens $\times 6 = 540$.