Question

the number 61 lies between which two perfect squares?
○ d. $9^2$ and $10^2$
○ a. $6^2$ and $8^2$
○ c. $8^2$ and $9^2$
○ b. $7^2$ and $8^2$

Explanation:

Step1: Calculate $7^2$

$7^2 = 7\times7 = 49$

Step2: Calculate $8^2$

$8^2 = 8\times8 = 64$

Step3: Verify 61's position

$49 < 61 < 64$

Answer:

B. $7^2$ and $8^2$