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a number, n, is added to 15 less than 3 times itself. the result is 101…

Question

a number, n, is added to 15 less than 3 times itself. the result is 101. which equation can be used to find the value of n?
$3n - 15 + n = 101$
$3n - 15 - n = 101$
$3n + 15 - n = 101$
$3n + 15 + n = 101$

Explanation:

Step1: Analyze "3 times itself"

3 times the number \( n \) is \( 3n \).

Step2: Analyze "15 less than 3 times itself"

15 less than \( 3n \) is \( 3n - 15 \).

Step3: Analyze "a number, \( n \), is added to..."

Adding \( n \) to \( 3n - 15 \) gives \( 3n - 15 + n \).

Step4: Analyze "The result is 101"

Set the expression equal to 101: \( 3n - 15 + n = 101 \).

Answer:

\( 3n - 15 + n = 101 \) (the first option)