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if an object has a density greater than water, it will... * 1 point a) …

Question

if an object has a density greater than water, it will...

  • 1 point

a) float on water
b) sink in water
c) stay suspended in water
d) dissolve in water
the mass of an object is 10g and the volume is 2ml what is the density

  • 1 point

1 g/ml
2 g/ml
3 g/ml
4 g/ml
5 g/ml
the mass of an object is 10g and the volume is 10ml what is the density

  • 1 point

1 g/ml
2 g/ml
3 g/ml
4 g/ml
5 g/ml
the mass of an object is 9g and the volume is 3ml what is the density

  • 1 point

1 g/ml
2 g/ml
3 g/ml
4 g/ml
5 g/ml

Explanation:

步骤1: 依据密度与浮沉关系

物体密度大于水会下沉。

步骤2: 计算密度公式

密度公式为$
ho=\frac{m}{V}$($
ho$表示密度,$m$表示质量,$V$表示体积)。

第二题

步骤1: 代入数据计算

$m = 10g$,$V = 2mL$,$
ho=\frac{10g}{2mL}=5g/mL$。

第三题

步骤1: 代入数据计算

$m = 10g$,$V = 10mL$,$
ho=\frac{10g}{10mL}=1g/mL$。

第四题

步骤1: 代入数据计算

$m = 9g$,$V = 3mL$,$
ho=\frac{9g}{3mL}=3g/mL$。

答案:

  1. b) Sink in water
  2. 5 g/mL
  3. 1 g/mL
  4. 3 g/mL

Answer:

步骤1: 依据密度与浮沉关系

物体密度大于水会下沉。

步骤2: 计算密度公式

密度公式为$
ho=\frac{m}{V}$($
ho$表示密度,$m$表示质量,$V$表示体积)。

第二题

步骤1: 代入数据计算

$m = 10g$,$V = 2mL$,$
ho=\frac{10g}{2mL}=5g/mL$。

第三题

步骤1: 代入数据计算

$m = 10g$,$V = 10mL$,$
ho=\frac{10g}{10mL}=1g/mL$。

第四题

步骤1: 代入数据计算

$m = 9g$,$V = 3mL$,$
ho=\frac{9g}{3mL}=3g/mL$。

答案:

  1. b) Sink in water
  2. 5 g/mL
  3. 1 g/mL
  4. 3 g/mL