Question

oh the function.
$f(x)=\sqrt{x - 1}$
four points on the graph of the function: the leftmost point and three additional points. then click on the graph - a - function button.

Explanation:

Step1: Find the domain

For the function $f(x)=\sqrt{x - 1}$, the expression under the square - root must be non - negative. So $x-1\geq0$, which gives $x\geq1$. The leftmost point occurs when $x = 1$.

Step2: Calculate the leftmost point

When $x = 1$, $f(1)=\sqrt{1 - 1}=0$. So the leftmost point is $(1,0)$.

Step3: Choose additional $x$ values

Let $x = 2$, then $f(2)=\sqrt{2 - 1}=1$. The point is $(2,1)$.
Let $x = 5$, then $f(5)=\sqrt{5 - 1}=2$. The point is $(5,2)$.
Let $x = 10$, then $f(10)=\sqrt{10 - 1}=3$. The point is $(10,3)$.

Answer:

The four points are $(1,0),(2,1),(5,2),(10,3)$