Question

one estimate for the number of protons in betelgeuse is 2.16×10^58. the mass of one proton is about 1.67×10^(-27) kg. what is the total mass of all the protons in betelgeuse? approximate by finding the product of (2×10^58)×(2×10^(-27)). (2×10^58)×(2×10^(-27)) =?×10^? kilograms

Explanation:

Step1: Multiply the non - power - of - 10 parts

Multiply 2 and 2.
$2\times2 = 4$

Step2: Multiply the power - of - 10 parts

Use the rule $a^m\times a^n=a^{m + n}$. Here, $a = 10$, $m = 58$ and $n=-27$. So, $10^{58}\times10^{-27}=10^{58+( - 27)}=10^{31}$

Answer:

$4\times10^{31}$