Question

one way you can start solving is to make sure there are only f terms on one side. what move can you make to both sides of the equation to get rid of the \\(\frac{2}{3}f\\) on the left, while keeping the equation balanced? \\(\frac{2}{3}f + 5 = f + 15\\) options: add \\(\frac{2}{3}f\\) to both sides, divide both sides by \\(\frac{2}{3}f\\), subtract \\(\frac{2}{3}f\\) from both sides, multiply both sides by \\(\frac{2}{3}f\\)

Explanation:

Step1: Identify target term

We aim to remove $\frac{2}{3}f$ from the left side.

Step2: Apply inverse operation

To eliminate $\frac{2}{3}f$, subtract it from both sides, since $\frac{2}{3}f - \frac{2}{3}f = 0$.
Left side after operation: $\frac{2}{3}f + 5 - \frac{2}{3}f = 5$
Right side after operation: $f + 15 - \frac{2}{3}f = \frac{1}{3}f + 15$
The equation remains balanced.

Answer:

Subtract $\frac{2}{3}f$ from both sides