Question

one way you can start solving is to make sure there are only f terms on one side. what move can you make to both sides of the equation to get rid of the \\(\frac{2}{3}f\\) on the left, while keeping the equation balanced? \\(\frac{2}{3}f + 5 = f + 15\\) options: subtract \\(\frac{2}{3}f\\) from both sides; add \\(\frac{2}{3}f\\) to both sides; multiply both sides by \\(\frac{2}{3}f\\); divide both sides by \\(\frac{2}{3}f\\)

Explanation:

Step1: Identify target term

We aim to remove $\frac{2}{3}f$ from the left side of $\frac{2}{3}f + 5 = f + 15$.

Step2: Apply inverse operation

Subtract $\frac{2}{3}f$ from both sides to maintain balance, eliminating $\frac{2}{3}f$ on the left:
$\frac{2}{3}f + 5 - \frac{2}{3}f = f + 15 - \frac{2}{3}f$
Simplifies to: $5 = \frac{1}{3}f + 15$

Answer:

Subtract $\frac{2}{3}f$ from both sides