Question

c. open ended describe how the graph would be different if yazmins jogging rate were a different constant.

Explanation:

Yazmin's jogging rate is the slope of the distance - time graph (since distance = rate×time, so in the form \(y = mx + b\), where \(y\) is distance, \(x\) is time, \(m\) is the rate (slope), and \(b\) is the y - intercept, usually 0 for starting from a fixed point). If the rate (slope) changes:

• If the new rate is greater than the original rate, the line on the graph (representing distance vs. time) will be steeper. This is because for the same amount of time, a higher rate means a greater distance covered, so the line rises more quickly as time increases.
• If the new rate is less than the original rate, the line on the graph will be less steep. Because for the same time interval, a lower rate results in a smaller distance covered, so the line rises more slowly as time increases.

Answer:

If Yazmin’s jogging rate (the slope of the distance - time graph) were a different constant:

• If the new rate is greater than the original, the graph’s line (distance vs. time) becomes steeper (rises more per unit time).
• If the new rate is less than the original, the graph’s line becomes less steep (rises less per unit time).