Question

order the expressions from least to greatest. $2^3 - 2^1$ $3^2$ $2^1 + 3^1$

Explanation:

Step1: Calculate \(2^{3}-2^{1}\)

First, calculate the exponents: \(2^{3}=8\) and \(2^{1} = 2\). Then subtract: \(8 - 2=6\).

Step2: Calculate \(3^{2}\)

\(3^{2}=3\times3 = 9\).

Step3: Calculate \(2^{1}+3^{1}\)

\(2^{1}=2\) and \(3^{1}=3\), then add: \(2 + 3=5\).

Step4: Order the results

We have the results \(5\) (from \(2^{1}+3^{1}\)), \(6\) (from \(2^{3}-2^{1}\)), and \(9\) (from \(3^{2}\)). So from least to greatest, the order is \(2^{1}+3^{1}\), \(2^{3}-2^{1}\), \(3^{2}\).

Answer:

\(2^{1}+3^{1}\), \(2^{3}-2^{1}\), \(3^{2}\)