Question

order these numbers from least to greatest.
-3.12, \\(\sqrt{8}\\), \\(-\frac{52}{16}\\), \\(-3.\overline{2}\\)
-3.12 \\(\sqrt{8}\\) \\(-\frac{52}{16}\\) \\(-3.\overline{2}\\)
\\(\square < \square < \square < \square\\)

Explanation:

Step1: Convert all to decimals

$-3.12$; $\sqrt{8}\approx2.828$; $-\frac{52}{16}=-3.25$; $-3.\overline{2}=-3.222...$

Step2: Compare decimal values

Negative numbers: $-3.25 < -3.222... < -3.12$; Positive number: $2.828$ is largest

Step3: Order from least to greatest

Arrange the original numbers by their decimal values

Answer:

$-\frac{52}{16} < -3.\overline{2} < -3.12 < \sqrt{8}$