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page 265 - solve for t #4: blake writes a correct equation to represent…

Question

page 265 - solve for t
#4: blake writes a correct equation to represent the measures of the angles in the diagram. (draw!)
3t = 90
answer: ______
page 266 - solve for n
#10: 18 = 9/10 n
exit ticket: solve each equation algebraically. use substitution to check your solution.
a. n/7 = 14
answer: ______
b. 3.49 = 8.5
answer: ______

Explanation:

Response
Part 1: Solve for \( t \) in \( 3t = 90 \)

Step 1: Isolate \( t \)

To solve for \( t \), divide both sides of the equation \( 3t = 90 \) by 3.
\[
\frac{3t}{3}=\frac{90}{3}
\]

Step 2: Simplify

Simplifying both sides gives \( t = 30 \).

Step 1: Isolate \( n \)

Multiply both sides of the equation \( 18=\frac{9}{10}n \) by the reciprocal of \( \frac{9}{10} \), which is \( \frac{10}{9} \).
\[
18\times\frac{10}{9}=\frac{9}{10}n\times\frac{10}{9}
\]

Step 2: Simplify

Simplify the left side: \( 18\times\frac{10}{9} = 2\times10 = 20 \). The right side simplifies to \( n \). So \( n = 20 \).

Step 1: Isolate \( m \)

Multiply both sides of the equation \( \frac{m}{7}=14 \) by 7.
\[
\frac{m}{7}\times7 = 14\times7
\]

Step 2: Simplify

Simplifying both sides gives \( m = 98 \).

Answer:

\( t = 30 \)

Part 2: Solve for \( n \) in \( 18=\frac{9}{10}n \)