QUESTION IMAGE
Question
part a: identification (problems 1 - 6)
instructions: determine the number of significant digits in each measurement.
- 0.00456 g
- 3.070 cm
- 500 ml
- 2.40×10⁴ kg
- 0.0800 m
- 1,205,000 atoms
part b: rounding (problems 7 - 12)
instructions: round each number to the specified number of significant digits.
- round 45.678 to 3 significant digits
- round 0.008934 to 2 significant digits
- round 1,567,890 to 4 significant digits
- round 23.456 to 2 significant digits
- round 0.07845 to 3 significant digits
- round 9.9999 to 3 significant digits
part c: addition and subtraction (problems 13 - 24)
instructions: perform the calculation and express your answer with the correct number of significant digits.
- 12.45 + 3.2+0.678 =
- 45.67 - 12.3 =
- 123.4 + 56.78 - 9.123 =
- 0.0456 + 1.23+0.789 =
- 234.5 - 12.67 =
- 0.123 + 45.6 + 2.34 =
Part A: Identification of Significant Digits
1. 0.00456 g
The leading zeros are not significant. So, there are 3 significant digits.
2. 3.070 cm
The zeros between non - zero digits and trailing zeros after a decimal point are significant. So, there are 4 significant digits.
3. 500 mL
If no decimal point is present, trailing zeros may or may not be significant. Assuming standard rules without further context, there is 1 significant digit.
4. 2.40×10⁴ kg
In scientific notation, all digits in the coefficient are significant. So, there are 3 significant digits.
5. 0.0800 m
Leading zeros are not significant, but trailing zeros after a non - zero digit and a decimal point are significant. So, there are 3 significant digits.
6. 1,205,000 atoms
Trailing zeros without a decimal point are not significant. So, there are 4 significant digits.
Part B: Rounding
7. Round 45.678 to 3 significant digits
The fourth digit is 7. Since 7≥5, we round up the third digit. So, 45.7.
8. Round 0.008934 to 2 significant digits
The third digit is 3. Since 3<5, we keep the first two non - zero digits. So, 0.0089.
9. Round 1,567,890 to 4 significant digits
The fifth digit is 8. Since 8≥5, we round up the fourth digit. In scientific notation, 1.568×10⁶.
10. Round 23.456 to 2 significant digits
The third digit is 4. Since 4<5, we keep the first two digits. So, 23.
11. Round 0.07845 to 3 significant digits
The fourth digit is 5. Since 5≥5, we round up the third digit. So, 0.0785.
12. Round 9.9999 to 3 significant digits
The fourth digit is 9. Since 9≥5, we round up the third digit. So, 10.0.
Part C: Addition and Subtraction
13. 12.45+3.2 + 0.678
First, add the numbers: 12.45+3.2+0.678 = 16.328. The least number of decimal places among the numbers being added is 1 (in 3.2). So, we round to 16.3.
14. 45.67−12.3
Subtract: 45.67−12.3 = 33.37. The least number of decimal places among the numbers is 1 (in 12.3). So, we round to 33.4.
15. 123.4+56.78−9.123
First, add 123.4 and 56.78: 123.4+56.78 = 180.18. Then subtract 9.123: 180.18−9.123 = 171.057. The least number of decimal places is 1 (in 123.4). So, we round to 171.1.
16. 0.0456+1.23+0.789
Add: 0.0456+1.23+0.789 = 2.0646. The least number of decimal places is 2 (in 1.23). So, we round to 2.06.
17. 234.5−12.67
Subtract: 234.5−12.67 = 221.83. The least number of decimal places is 1 (in 234.5). So, we round to 221.8.
18. 0.123+45.6+2.34
Add: 0.123+45.6+2.34 = 48.063. The least number of decimal places is 1 (in 45.6). So, we round to 48.1.
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- 3 significant digits
- 4 significant digits
- 1 significant digit
- 3 significant digits
- 3 significant digits
- 4 significant digits
- 45.7
- 0.0089
- 1.568×10⁶
- 23
- 0.0785
- 10.0
- 16.3
- 33.4
- 171.1
- 2.06
- 221.8
- 48.1