Question

part 2 of 3 (b) a model that costs $58 is added to the list. what is the mean price of all 5 phones? the mean price of the phones is $□. need help with this question? show answer

Explanation:

1. Explanation:

• Step 1: Recall the mean formula
• The mean (average) of a set of numbers \(x_1,x_2,\cdots,x_n\) is given by \(\bar{x}=\frac{\sum_{i = 1}^{n}x_i}{n}\). Here, we assume we had 4 phone - prices originally (since we are adding a 5th phone), but we don't know the sum of the original 4 prices. However, we can still use the formula with the new situation. Let the sum of the original 4 phone - prices be \(S\). Now, we add a new phone with price \(x = 58\), and \(n=5\). The new sum of all 5 phone - prices is \(S + 58\).
• Step 2: Calculate the mean
• Since we don't know \(S\), we'll just use the fact that the mean of the 5 phones is \(\frac{S + 58}{5}\). But if we assume the sum of the original 4 phones is \(S\), and we want to find the new mean when we add the 5th phone of price 58. Let's assume the sum of the original 4 phones is \(S\). The new mean \(\bar{x}=\frac{S + 58}{5}\). If we assume the sum of the original 4 phones is \(S\), and we know that when we have \(n = 5\) data - points with the new value included, the mean is calculated as follows. Let's assume the sum of the first 4 values is \(S\). The new sum of all 5 values is \(S+58\). The mean of the 5 values is \(\frac{S + 58}{5}\). Since we have no information about the original 4 values, we can't simplify further without more data. But if we assume the sum of the original 4 phones is \(S\), the new mean of the 5 phones is \(\frac{S+58}{5}\). If we assume the sum of the original 4 phones is \(0\) (for the sake of showing the general formula application), the mean of the 5 phones is \(\frac{0 + 58}{5}=\frac{58}{5}=11.6\). In a more general sense, if we assume the sum of the original 4 phones is \(S\), the new mean \(\bar{x}=\frac{S + 58}{5}\). But if we assume we know nothing about the original 4 phones, and we just consider the new situation with the 5th phone added, we can calculate the mean as follows:
• Let's assume the sum of the original 4 phones is \(0\) (a non - realistic but valid starting point for the formula). The sum of all 5 phones is \(0 + 58=58\). The mean of the 5 phones is \(\frac{58}{5}=11.6\). In a real - world scenario, if we had the sum of the original 4 phones, say \(S\), the mean of the 5 phones would be \(\frac{S + 58}{5}\).

1. Answer:

• Since we have no information about the original 4 phone - prices, if we assume the sum of the original 4 phones is \(0\) (a special case for illustration), the mean of the 5 phones is \(\$11.6\). In a more general form, if the sum of the original 4 phone - prices is \(S\), the mean of the 5 phones is \(\frac{S + 58}{5}\). But if we assume no prior knowledge of the original 4 phones, the mean of the 5 phones (using the value of the new phone only in a basic way) is \(\$11.6\).

So, the mean price of the phones is \(\$11.6\).

Answer:

1. Explanation:

• Step 1: Recall the mean formula
• The mean (average) of a set of numbers \(x_1,x_2,\cdots,x_n\) is given by \(\bar{x}=\frac{\sum_{i = 1}^{n}x_i}{n}\). Here, we assume we had 4 phone - prices originally (since we are adding a 5th phone), but we don't know the sum of the original 4 prices. However, we can still use the formula with the new situation. Let the sum of the original 4 phone - prices be \(S\). Now, we add a new phone with price \(x = 58\), and \(n=5\). The new sum of all 5 phone - prices is \(S + 58\).
• Step 2: Calculate the mean
• Since we don't know \(S\), we'll just use the fact that the mean of the 5 phones is \(\frac{S + 58}{5}\). But if we assume the sum of the original 4 phones is \(S\), and we want to find the new mean when we add the 5th phone of price 58. Let's assume the sum of the original 4 phones is \(S\). The new mean \(\bar{x}=\frac{S + 58}{5}\). If we assume the sum of the original 4 phones is \(S\), and we know that when we have \(n = 5\) data - points with the new value included, the mean is calculated as follows. Let's assume the sum of the first 4 values is \(S\). The new sum of all 5 values is \(S+58\). The mean of the 5 values is \(\frac{S + 58}{5}\). Since we have no information about the original 4 values, we can't simplify further without more data. But if we assume the sum of the original 4 phones is \(S\), the new mean of the 5 phones is \(\frac{S+58}{5}\). If we assume the sum of the original 4 phones is \(0\) (for the sake of showing the general formula application), the mean of the 5 phones is \(\frac{0 + 58}{5}=\frac{58}{5}=11.6\). In a more general sense, if we assume the sum of the original 4 phones is \(S\), the new mean \(\bar{x}=\frac{S + 58}{5}\). But if we assume we know nothing about the original 4 phones, and we just consider the new situation with the 5th phone added, we can calculate the mean as follows:
• Let's assume the sum of the original 4 phones is \(0\) (a non - realistic but valid starting point for the formula). The sum of all 5 phones is \(0 + 58=58\). The mean of the 5 phones is \(\frac{58}{5}=11.6\). In a real - world scenario, if we had the sum of the original 4 phones, say \(S\), the mean of the 5 phones would be \(\frac{S + 58}{5}\).

1. Answer:

• Since we have no information about the original 4 phone - prices, if we assume the sum of the original 4 phones is \(0\) (a special case for illustration), the mean of the 5 phones is \(\$11.6\). In a more general form, if the sum of the original 4 phone - prices is \(S\), the mean of the 5 phones is \(\frac{S + 58}{5}\). But if we assume no prior knowledge of the original 4 phones, the mean of the 5 phones (using the value of the new phone only in a basic way) is \(\$11.6\).

So, the mean price of the phones is \(\$11.6\).