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perform the operation and write the result in standard form. (7x - 2) +…

Question

perform the operation and write the result in standard form.
(7x - 2) + (3x^2 - x + 11)
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Explanation:

Step1: Remove parentheses

To add the two polynomials, we first remove the parentheses. The expression \((7x - 2)+(3x^{2}-x + 11)\) becomes \(7x - 2+3x^{2}-x + 11\) since there are no negative signs outside the parentheses to change the signs of the terms inside.

Step2: Combine like terms

  • For the \(x^{2}\) term: There is only one \(x^{2}\) term, which is \(3x^{2}\).
  • For the \(x\) terms: We have \(7x\) and \(-x\). Combining these, we get \(7x - x=6x\).
  • For the constant terms: We have \(-2\) and \(11\). Combining these, we get \(-2 + 11 = 9\).

Putting it all together, we have \(3x^{2}+6x + 9\).

Answer:

\(3x^{2}+6x + 9\)