Question

the perimeter of δabc is 13 cm. it was dilated to create δabc. what is the perimeter of δabc? 13 cm 26 cm 39 cm 52 cm

Explanation:

Step1: Find dilation factor

Dilation factor $k=\frac{OB'}{OB}=\frac{15}{5} = 3$.

Step2: Calculate new perimeter

Perimeter of $\triangle A'B'C'=k\times$ perimeter of $\triangle ABC = 3\times13=39$ cm.

Answer:

39 cm