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4.2 perimeter of quadrilaterals and triangles a rectangular cupboard ha…

Question

4.2 perimeter of quadrilaterals and triangles
a rectangular cupboard has a length of 6m and a perimeter of 20 m. find the width of the cupboard.

Explanation:

Step1: Recall perimeter formula

The perimeter formula for a rectangle is $P = 2(l + w)$, where $P$ is perimeter, $l$ is length and $w$ is width. Given $P = 20$ m and $l=6$ m, we substitute into the formula: $20 = 2(6 + w)$.

Step2: Divide both sides by 2

Dividing both sides of the equation $20 = 2(6 + w)$ by 2 gives $\frac{20}{2}=\frac{2(6 + w)}{2}$, which simplifies to $10=6 + w$.

Step3: Solve for width

Subtract 6 from both sides of the equation $10 = 6+w$. So, $w=10 - 6$.

Answer:

4