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the perimeter of a rectangle is 56 cm. the length is 3 times the width …

Question

the perimeter of a rectangle is 56 cm. the length is 3 times the width minus 4 cm. what is the width? 8 12 5 7 11

Explanation:

Step1: Define variables

Let the width of the rectangle be $w$ cm. Then the length $l=(3w - 4)$ cm.

Step2: Use perimeter formula

The perimeter formula of a rectangle is $P = 2(l + w)$. Given $P = 56$ cm, we substitute $l$ and $P$ into the formula: $56=2((3w - 4)+w)$.

Step3: Simplify the equation

First, simplify the expression inside the parentheses: $56 = 2(4w-4)$. Then distribute the 2: $56=8w - 8$.

Step4: Solve for $w$

Add 8 to both sides of the equation: $56 + 8=8w$, so $64 = 8w$. Divide both sides by 8: $w=\frac{64}{8}=8$.

Answer:

A. 8