Question

the perimeter of the triangle below is 58 units. find the length of side $overline{bc}$.
write your answer without variables.
$bc = \square$
the side lengths of the triangle: $ac=3z$, $ab=2z+3$, $bc=z+1$

Explanation:

Step1: Sum sides for perimeter

$3z + (2z + 3) + (z + 1) = 58$

Step2: Combine like terms

$6z + 4 = 58$

Step3: Isolate z term

$6z = 58 - 4$
$6z = 54$

Step4: Solve for z

$z = \frac{54}{6} = 9$

Step5: Calculate BC length

$BC = z + 1 = 9 + 1$

Answer:

10