Question

period date decide whether the given ordered pair is a solution to the system of equations. 1. $y = 2x - 6$ $y = 8 - x$ $(4,2)$ 2. $y = \frac{2}{3}x + 4$ $y = -x - 1$ $(-3,2)$ 3. $y = 5x + 12$ $y = -x$ $(-2,2)$ 4. $y = x - 6$ $y = -2x + 9$ $(5,-1)$ 5. $y = 3x + 5$ $y = -\frac{3}{5}x + \frac{2}{5}$ $(-1,-2)$ 6. $y = -\frac{4}{3}x + 3$ $y = -5x - 8$ $(-3,7)$ 7. which of the following ordered pairs is a solution to the system of equation? select all that apply. $y = 2x - 6$ $y = -\frac{7}{2}x - 6$ a. $(2,-10)$ b. $(-3,13)$ c. $(4,-9)$ 8. kerylin says that there is no solution to the system of equations in #7. do you agree or disagree with kerylin? explain your reasoning.

Explanation:

1.

Step1: Test first equation

Substitute $(4,2)$ into $y=2x-6$:
$2 = 2(4)-6 = 8-6=2$ (true)

Step2: Test second equation

Substitute $(4,2)$ into $y=8-x$:
$2 = 8-4=4$ (false)

Step1: Test first equation

Substitute $(-3,2)$ into $y=\frac{2}{3}x+4$:
$2 = \frac{2}{3}(-3)+4 = -2+4=2$ (true)

Step2: Test second equation

Substitute $(-3,2)$ into $y=-x-1$:
$2 = -(-3)-1=3-1=2$ (true)

Step1: Test first equation

Substitute $(-2,2)$ into $y=5x+12$:
$2 = 5(-2)+12 = -10+12=2$ (true)

Step2: Test second equation

Substitute $(-2,2)$ into $y=-x$:
$2 = -(-2)=2$ (true)

Answer:

No

---

2.