Question

a piece of copper ($c = 0.385\frac{j}{gcdot^{circ}c}$) undergoing a temperature change from $150^{circ}c$ to $225^{circ}c$ absorbs 3500 joules of energy. what is the mass of the piece of copper? express the answer to the nearest whole number. grams

Explanation:

Step1: Calculate temperature change

$\Delta T=225 - 150=75^{\circ}C$

Step2: Use heat - energy formula

The formula for heat energy is $Q = mc\Delta T$, where $Q$ is heat energy, $m$ is mass, $c$ is specific heat capacity. We need to solve for $m$, so $m=\frac{Q}{c\Delta T}$.

Step3: Substitute values

Given $Q = 3500\ J$, $c=0.385\ \frac{J}{g^{\circ}C}$, and $\Delta T = 75^{\circ}C$. Then $m=\frac{3500}{0.385\times75}$.

Step4: Calculate mass

$m=\frac{3500}{28.875}\approx121.21\ g$. Rounding to the nearest whole number, $m = 122\ g$.

Answer:

122