Question

point $p$ is the image of $p(-2, -2)$ under a translation by 1 unit to the left and 3 units down. what are the coordinates of $p$? $(square, square)$

Explanation:

Step1: Adjust x-coordinate (left 1 unit)

$x' = -2 - 1 = -3$

Step2: Adjust y-coordinate (down 3 units)

$y' = -2 - 3 = -5$

Answer:

$(-3, -5)$