Question

point $q$ is the image of $q(0,6)$ under the translation $(x,y)\to(x + 7,y - 5)$. what are the coordinates of $q$?

Explanation:

Step1: Find the x - coordinate of Q'

Given the translation rule $(x,y)\to(x + 7,y - 5)$ and the point $Q(0,6)$. For the x - coordinate, substitute $x = 0$ into $x+7$. So, $x'=0 + 7=7$.

Step2: Find the y - coordinate of Q'

Substitute $y = 6$ into $y - 5$. So, $y'=6-5 = 1$.

Answer:

$(7,1)$