Question

practice solve each subtraction to elimina1. \

$$\begin{cases} 3x - 2y = 14 \\\\ 2x + 2y = 6 \\end{cases}$$

1. -8x + 6y = -12\\10x - 6y = 0

Explanation:

Step1: Eliminate y by adding equations

$$(3x - 2y) + (2x + 2y) = 14 + 6$$
$$5x = 20$$

Step2: Solve for x

$$x = \frac{20}{5} = 4$$

Step3: Substitute x=4 into second equation

$$2(4) + 2y = 6$$
$$8 + 2y = 6$$

Step4: Solve for y

$$2y = 6 - 8 = -2$$
$$y = \frac{-2}{2} = -1$$
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Step1: Eliminate y by adding equations

$$(-8x + 6y) + (10x - 6y) = -12 + 0$$
$$2x = -12$$

Step2: Solve for x

$$x = \frac{-12}{2} = -6$$

Step3: Substitute x=-6 into second equation

$$10(-6) - 6y = 0$$
$$-60 - 6y = 0$$

Step4: Solve for y

$$-6y = 60$$
$$y = \frac{60}{-6} = -10$$

Answer:

1. $x=4$, $y=-1$
2. $x=-6$, $y=-10$