Question

1. the probability of rolling a 5 on a six - sided number cube is 1/6. what is the probability of not rolling a 5 on a six - sided number cube? express your answer as a fraction.

Explanation:

Step1: Recall probability rule

The sum of the probability of an event happening and the probability of it not happening is 1. Let $P(A)$ be the probability of rolling a 5 and $P(\overline{A})$ be the probability of not rolling a 5. So $P(A)+P(\overline{A}) = 1$.

Step2: Substitute known value

We know that $P(A)=\frac{1}{6}$. Then $P(\overline{A})=1 - P(A)$.

Step3: Calculate result

$P(\overline{A})=1-\frac{1}{6}=\frac{6 - 1}{6}=\frac{5}{6}$.

Answer:

$\frac{5}{6}$