Question

problem 17: (first taught in lesson 20) find the measure of ∠aob. after you enter your answer press go. m∠aob =

Explanation:

Step1: Set up an equation

Since $\angle AOC = 90^{\circ}$ and $\angle AOC=\angle AOB+\angle BOC$, we have $(3x - 1)+(7x + 1)=90$.

Step2: Simplify the left - hand side

Combining like terms, $3x-1 + 7x + 1=10x$. So, $10x=90$.

Step3: Solve for x

Dividing both sides by 10, we get $x = 9$.

Step4: Find the measure of $\angle AOB$

Substitute $x = 9$ into the expression for $\angle AOB$ which is $3x-1$. So, $\angle AOB=3\times9 - 1=27 - 1=26^{\circ}$.

Answer:

$26^{\circ}$