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Question
problem 22: (first taught in lesson 16) ∠a and ∠d are supplementary. if m∠a = 9y - 19 and m∠d = 3y - 5, find m∠a. after you enter your answer press go. m∠a =
Step1: Use supplementary - angle property
$(9y - 19)+(3y - 5)=180$
Step2: Combine like - terms
$9y+3y-19 - 5 = 180$
$12y-24 = 180$
Step3: Isolate the variable term
$12y=180 + 24$
$12y=204$
Step4: Solve for y
$y=\frac{204}{12}=17$
Step5: Find m∠A
$m\angle A=9y - 19$
Substitute $y = 17$: $m\angle A=9\times17-19$
$m\angle A = 153-19=128$
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$128$