Question

(a) problem 8: (first taught in lesson 41) if $overline{bp}perpoverline{ac}$, then $overline{bp}$ is a(n) _____ of $\triangle abc$. after you pick your answer press go. a. hypotenuse b. altitude c. leg d. median e. perpendicular bisector

Explanation:

Step1: Recall definitions

The altitude of a triangle is a line - segment from a vertex perpendicular to the opposite side.

Step2: Analyze given condition

Given $\overline{BP}\perp\overline{AC}$, where $B$ is a vertex of $\triangle ABC$ and $\overline{AC}$ is the opposite side. So $\overline{BP}$ is an altitude of $\triangle ABC$.

Answer:

B. altitude